Given cos0 = 5/6 ans angle 0 is in quadrant 1, what is the exact value of sin 0 in simplest form ?
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Answer:
[tex]\frac{\sqrt{11}}{6}[/tex]
Step-by-step explanation:
formula : cos²θ + sin²θ = 1
then sin²θ = 1 - cos²θ
then sin²θ = 1 - (5/6)²
then sin²θ = 1 - 25/36
= (36 - 25)/36
= 11/36
sin²θ = 11/36 ⇒ sinθ = √(11)/6 = =0.552770798393