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Solve the system of linear equations below.

6x + 3y = 33
4x + y = 15

A. x = 2, y = 7

B. x = -13, y = 7

C. x = - , y = 12

D. x = 5, y = 1

Solve the system of linear equations below 6x 3y 33 4x y 15 A x 2 y 7 B x 13 y 7 C x y 12 D x 5 y 1 class=

Respuesta :

rishavbasista

Answer:

6×2+3×7=33

12+21=33

33=33

equal

4×2+7=15

8+7=15

15=15

equal

x=2,y=7

Answer: x=2, y=7

Step-by-step explanation:

6x+3y=33.................. (1)

4x+y=15.......................(2)

Using elimination method multiply equation one by 1 and equation 2 by 3

6x+3y=33...................(3)

12x+3y=45....................(4)

Eliminating y

We have

6x+3y=33

-

12x+3y=45

The single equation becomes

-6x+0=-12

-6x=-12

Minus cancelled minus

6x=12

x=12/6

x=2

To find y substitute x=2 in equation 1

6x+3y=33

6(2)+3y=33

12+3y=33

3y=33-12

3y=21

y= 21/3

y=7

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