Answer: 2.56atm
Explanation:
P1/T1=P2/T2
P1T2=P2T1
P2=P1T2/T1
P1=2.3atm
P2=?
T1=0+273=273k
T2=32+273=305k
P2=2.3*305/273
P2=701.5/273
P2=2.56atm
Answer:
The pressure will increase to a pressure of 2.6 atm
Explanation:
Step 1: Data given
Volume = 500 mL = 0.500L
Pressure = 2.3 atm
Temperature = 0°C = 273 K
Temperature is warmed to 37 °C = 310 K
Volume will stay constant
Step 2: Calculate the new pressure
p1/T1 = p2/T2
⇒with p1 = the initial pressure = 2.3 atm
⇒with T1 = the initial temperature = 0 °C = 273 K
⇒with p2 = the new pressure = TO BE DETERMINED
⇒with T2 = the new temperature = 37 °C = 310 K
2.3 atm / 273 K = p2 / 310 K
p2 = 2.6 atm
The pressure will increase to a pressure of 2.6 atm
