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The LR5 is the specialist submarine for underwater rescue. The average density of seawater is 1028 kg/ m3.
i. Calculate the increase in pressure as LR5 descends from the surface to a depth of 700m.(g=10m/s2 )

Respuesta :

rafaleo84

Answer:

P = 7196 [kPa]

Explanation:

We can solve this problem using the expression that defines the pressure depending on the height of water column.

P = dens*g*h

where:

dens = 1028 [kg/m^3]

g = 10 [m/s^2]

h = 700 [m]

Therefore:

P = 1028*10*700

P = 7196000 [Pa]

P = 7196 [kPa]