The magnetic field of the brain has been measured to be approximately 3.0×10−12T. Although the currents that cause this field are quite complicated, we can get a rough estimate of their size by modeling them as a single circular current loop 16 cm (the width of a typical head) in diameter. What current is needed to produce such a field at the center of the loop?

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AFOKE88 AFOKE88 · Answer 1 · 2020-03-15T03:07:07+01:00

Answer:

I = 3.82 x 10^(−7) A

Explanation:

The formula for magnetic field at the centre of a loop is given as;

B = μI/2R

Where μ is a magnetic constant with a value of 12.57 × 10^(−7) H/m.

I = current

R = Radius = 16/2 = 8cm or 0.08m

B = 3.0×10^(−12) T

So making I the subject of the formula, we obtain ;

I = 2RB/μ

Thus, I = [2 x 0.08 x 3.0×10^(−12)]/12.57 × 10^(−7)

I = 3.82 x 10^(−7) A

sp10925 sp10925 · Answer 2 · 2022-06-07T02:08:31+02:00

The current needed to produce such a field at the center of the loop is 3.82 x 10⁻⁷ A

The magnetic field is the region of space where a charged object experiences magnetic force when it is moving.

The formula for magnetic field at the center of a loop is given as;

B = μI/2R

Where μ is a magnetic constant with a value of 12.57 × 10⁻⁷ H/m, radius R= 16/2 = 8cm or 0.08m and magnetic field B = 3.0×10⁻¹² T

If I is the current then magnetic field will be represented as

3.0×10⁻¹² T= 12.57 × 10⁻⁷ x I / (2 x 0.08)

Solving for current I,

I = 3.82 x 10⁻⁷ A

Thus, the current needed to produce such a field at the center of the loop is 3.82 x 10⁻⁷ A.

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