You are given

n = 8

measurements: 5, 3, 7, 9, 7, 6, 4, 8.

(a) Calculate the range, R.

R =


(b) Calculate the sample mean, x. (Enter your answer to three decimal places.)

x =


(c) Calculate the sample variance, s2, and standard deviation, s. (Round your variance to four decimal places and your standard deviation to two decimal places.)

s2 =

s =


(d) Compare the range and the standard deviation. The range is approximately how many standard deviations? (Round your answer to two decimal places.)

Respuesta :

Answer:

a) Range: The range is easily calculated by subtracting the lowest value from the highest value in the data set.

R = Maximum -minimum = 9-3 = 6,   So, R=6

b) Mean is the sum of all values in data set divided by number of elements in the data set

Mean = sum of all elements/total elements = 49/8 = 6.125

Mean = 6.125

c) Variance and Standard Deviation:

Variance is a measure of by how much the values in the data set are likely to differ from the mean of the values.

[tex]s^2 ={\frac{1}{n-1} \sum_{i=1}^n (x_i-\bar{x})^2$[/tex]

[tex]s^{2}[/tex] = 3.6094

Standard Deviation is square root of variance which is 1.90

s=1.90

d) Ration of range and standard deviation is

Range/s = 3.16, SO the range is 3.16 times the standard deviation.