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Write the equilibrium‑constant expression for the reaction

A(s)+3B(l)↽−−⇀2C(aq)+D(aq)
in terms of [A], [B], [C], and [D], as needed.

Note that Kc, which is sometimes symbolized as Keq, denotes that the equilibrium constant is expressed using molar concentrations. For this question, Kc means the same thing as Keq.

Kc=

Respuesta :

joseaaronlara

Answer:

The answer to your question is Kc = Keq = [C]²[D]

Explanation:

Balanced chemical reaction

                A (s)  +  3B (l)  ⇔  2C (aq)  +  D (aq)

Kc = Keq = [tex]\frac{[C]^{2} [D]}{[A][B]^{3}}[/tex]

But, remember that reactants or products in liquid or solid state must not be considered.

So, A and B must not be considered.

And the Equilibrium constant is:

                                      Kc = Keq = [C]²[D]

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