A chemist prepares a solution of potassium permanganate (KMnO 4)by measuring out 4.6 mu mol of potassium permanganate into a 300. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mmol/L of the chemist's potassium permanganate solution. Round your answer to 2significant digits.

Respuesta :

Answer: The concentration of potassium permanganate solution is 0.015 mM

Explanation:

To calculate the molarity of solution, we use the equation:

[tex]\text{Milli molarity of the solution}=\frac{\text{Milli moles of solute}\times 1000}{\text{Volume of solution (in mL)}}[/tex]

We are given:

Moles of solute = [tex]4.6\mu mol=4.6\times 10^{-3}mmol[/tex]    (Conversion factor: [tex]1mmol=1000\mu moles[/tex]

Volume of solution = 300 mL

Putting values in above equation, we get:

[tex]\text{Milli molarity of the solution}=\frac{4.6\times 10^{-3}\times 1000}{300}\\\\\text{Milli molarity of the solution}=0.015mM[/tex]

Hence, the concentration of potassium permanganate solution is 0.015 mM