The molar volume of a gas at STP occupies 22.4 L.
Option D
Explanation:
To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,
P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)
STP = 1 atm of pressure and 273 K for temperature
P = 1 atm
V = ?
n = 1 mole
R = 0.0821 atm L/mol K
T = 273 K
Using the equation,
[tex]\mathrm{PV}=\mathrm{nRT}[/tex]
[tex]V=\frac{n R T}{P}[/tex]
By substituting the above values, in the equation,
[tex]V=\frac{1 \times 0.082 \times 273}{1}=22.38\ L[/tex]
V = 22.38 L
