Answer:
Explanation:
Mass of gold deposited = 0.5 g
Molar mass of gold = 197 g/mol
Time, t = 6 hours
= 6 × 3600
= 12600 s
Number of moles = mass/molar mass
= 0.5/197
= 0.00254 mole
Assuming
Au --> Au+ + e-
Faraday constant = 9.65 x 104 C mol-1
Q = 96500 × 0.00254
= 244.924 C
Q = I × t
I = 244.924/12600
= 0.011 A
= 11.34 mA.