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When a 219.39-kg crate is pulled across a frictionless horizontal floor with a force of 800 N, directed 30° above the horizontal, the magnitude of the normal force of the floor on the crate is:a. 1560 Nb. 380 Nc. 680 Nd. 580 Ne. 1750 N

Respuesta :

Answer:

D. 580 N.

Explanation:

Given:

F = 800 N

Theta = 30°C

Mass, M = 219.39 kg

From Newton's second law,

On the x-axis,

Ft = M × a

Fx - Fk = M × a × × sin theta

Fk = N

N = 800 + 219.39 × sin 30

= 583.24 N

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