[tex]18.069 \times 10^{23[/tex] molecules of methane are present.
The molar concept is very necessary for solving this question. The molecular weight of methane is to be calculated.
The molecular weight of methane = [tex]12 + 1\times4[/tex] = 16.
So in 16 grams of methane, 1 mole of methane is present.
So, in 48.2 grams of methane, number of moles of methane present = 3.
In 1 mole of any substance, number of molecules of that substance present = [tex]6.023 \times 10^{23[/tex]
So,number of molecules present [tex]=18.069 \times 10^{23[/tex].
