Answer:
The inductance of this solenoid is 5.51 mH.
Explanation:
Given that,
length of the tube, l = 38 cm = 0.38 m
Diameter of the tube, d = 8.3 cm
Radius of the tube, r = 4.15 cm
The number of turns, N = 555
We need to find the inductance of this solenoid. It is given by the formula as :
[tex]L=\dfrac{\mu N^2A}{l}\\\\L=\dfrac{4\pi \times 10^{-7}\times 555^2\times \pi \times (4.15\times 10^{-2})^2}{0.38}\\\\L=0.00551\ H\\\\L=5.51\ mH[/tex]
So, the inductance of this solenoid is 5.51 mH. Hence, this is the required solution.
