Respuesta :
The molar concentration of the ammonia is 2.96 M.
Explanation:
In titration the known concentrated acid or base solution is added to unknown concentration solution until a neutral point is formed.
In titrations the formula used is
Macid x V acid = Mbase x V base
The volume must be in litre.
From the question it can be found that HCl is used to neutralize household ammonia.
Volume of HCl is 18.5 ml which is [tex]\frac{18.5}{1000}[/tex] L
molarity of the HCl is given 0.8 M
Volume of the base NH3 is given 5ml which is [tex]\frac{5}{1000}[/tex] L
Using the formula given above
Macid x V acid = Mbase x V base
Putting the values in the equation:
0.8 x 0.0185 = Mbase x 0.005
Mbase = [tex]\frac{0.8 x 0.0185}{0.005}[/tex]
Mbase = 2.96 M
Answer:
The molar concentration of the ammonia is 2.96 M.
Explanation:
it just is
