Respuesta :
Answer:
the longest wavelength of light that has sufficient energy to break the weakest bond in hydrogen peroxide is 842nm
Explanation:
Δ H = 142 kJ/mol
This is the energy for 1 mol of molecules.
For 1 molecule,
[tex]E = \frac{142000J}{1mol} \frac{1mol}{6.022 \times 10^2^3molecules} \\ = 2.358 \times 19^-^1^9J[/tex]
[tex]E = \frac{h_c}{\lambda}[/tex]
[tex]\lambda = \frac{h_c}{E} \\ = \frac{6.626 \times 10^-^3^4Js \times 2.998 \times 10^8m/s}{2.358 \times 19^-1^9J} \\= 8.42 \times 10^-^7\\\\=842nm[/tex]
the longest wavelength of light that has sufficient energy to break the weakest bond in hydrogen peroxide is 842nm
The longest wavelength of light that has sufficient energy to break the weakest bond in hydrogen peroxide is 828 nm.
The compound H2O2 has O-H and O-O bonds. The weakest bond in the molecule is the O-O bond with a bond energy of about 142 KJ/mol.
The energy of this bond in joules is obtained from;
E = [tex]142 * 10^3/6.02 * 10^23 = 2.359 * 10^-19 J[/tex]
Recall that;
E = hc/λ
Where;
E = energy of the photon
h = Plank's constant
c = speed of light
λ = wavelength
λ = hc/E
λ = [tex]6.6 * 10^-34 * 3 * 10^8/2.39 * 10^-19[/tex]
λ = 828 nm
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