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Hydrogen peroxide is sold commercially as an aqueous solution in brown bottles to protect it from light. Calculate the longest wavelength of light that has sufficient energy to break the weakest bond in hydrogen peroxide.

Respuesta :

Answer:

the longest wavelength of light that has sufficient energy to break the weakest bond in hydrogen peroxide is 842nm

Explanation:

Δ H = 142 kJ/mol  

This is the energy for 1 mol of molecules.

For 1 molecule,

[tex]E = \frac{142000J}{1mol} \frac{1mol}{6.022 \times 10^2^3molecules} \\ = 2.358 \times 19^-^1^9J[/tex]

[tex]E = \frac{h_c}{\lambda}[/tex]

[tex]\lambda = \frac{h_c}{E} \\ = \frac{6.626 \times 10^-^3^4Js \times 2.998 \times 10^8m/s}{2.358 \times 19^-1^9J} \\= 8.42 \times 10^-^7\\\\=842nm[/tex]

the longest wavelength of light that has sufficient energy to break the weakest bond in hydrogen peroxide is 842nm

The longest wavelength of light that has sufficient energy to break the weakest bond in hydrogen peroxide is  828 nm.

The compound H2O2 has O-H and O-O bonds. The weakest bond in the molecule is the O-O bond with a bond energy of about 142 KJ/mol.

The energy of this bond in joules is obtained from;

E = [tex]142 * 10^3/6.02 * 10^23 = 2.359 * 10^-19 J[/tex]

Recall that;

E = hc/λ

Where;

E = energy of the photon

h = Plank's constant

c = speed of light

λ = wavelength

λ = hc/E

λ = [tex]6.6 * 10^-34 * 3 * 10^8/2.39 * 10^-19[/tex]

λ = 828 nm

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