Answer:
The answer to your question is pH = 0.686
Explanation:
Data
Acetic acid = 20 ml
Final volume = 1.7 L
pH = ?
density = 1.05 g/ml
Process
1.- Calculate the mass of acetic acid
density = mass / volume
mass = density x volume
mass = 1.05 x 20
mass = 21 g
2.- Calculate the moles of acetic acid (CH₃COOH)
Molar mass = (12 x 2) + (16 x 2) + (4 x 1)
= 24 + 32 + 4
= 60 g
60 g of acetic acid ---------------- 1 mol
21 g of acetic acid ----------------- x
x = (21 x 1) / 60
x = 0.35 moles
3.- Calculate the concentration
Molarity = 0.35 moles / 1.70 L
= 0.206
4.- Calculate the pH
pH = -log[0.206]
pH = 0.686
