Answer:
0.208mole of CO2
Explanation:
First, let us calculate the number of mole of HC3H3O2 present.
Molarity of HC3H3O2 = 0.833 mol/L
Volume = 25 mL = 25/100 = 0.25L
Mole =?
Mole = Molarity x Volume
Mole = 0.833 x 0.25
Mole of HC3H3O2 = 0.208mole
Now, we can easily find the number of mole of CO2 produce by doing the following:
NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2
From the equation,
1mole of HC2H3O2 produced 1 mole of CO2.
Therefore, 0.208mole of HC2H3O2 will also produce 0.208mole of CO2
Answer:
For 0.0208 moles CH2H3O2 we'll have 0.0208 moles CO2 produced
Explanation:
Step 1: Data given
Volume of HC2H3O2 = 25 mL = 0.025 L
Concentration of HC2H3O2 = 0.833 mol / L
NaHCO3 is in excess
Step 2: The balanced equation
NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2
For 1 mol NaHCO3 we need 1 mol HC2H3O2 to produce 1 mol NaC2H3O2, 1 mol H2O and 1mol CO2
Step 3: Calculate moles HC2H3O2
Moles HC2H3O2 = concentration HC2H3O2 * volume solution
Moles HC2H3O2 = 0.833 mol/L * 0.025 L
Moles HC2H3O2 = 0.0208 moles
Step 4: calculate moles CO2
For 1 mol NaHCO3 we need 1 mol HC2H3O2 to produce 1 mol NaC2H3O2, 1 mol H2O and 1mol CO2
For 0.0208 moles CH2H3O2 we'll have 0.0208 moles CO2 produced
