Answer:
Jupiter's angular speed is 1.68*10^-8rad/s or 9.63*10^-6asec/s.
Explanation:
Jupiter completes one revolution of the sun in 3.74*10^8 seconds, this means that it travels around a complete circle, of 2π radians, in that time. So, we can express the Jupiter's angular speed as:
[tex]\omega=\frac{2\pi}{3.74*10^8s} =1.68*10^{-8}rad/s[/tex]
In words, Jupiter's angular speed is 1.68*10^-8 rad/s.
Now, to express it in arc-seconds per second, or asec/s, we have to multiply it by the factor [tex]\frac{3600asec}{2\pi rad}[/tex], and we get:
[tex]1.68*10^{-8}rad/s=9.63*10^{-6}asec/s[/tex]
Finally, the angular speed is equal to 9.63*10^-6asec/s.
