Answer:
The change in temperature of a coffee cup calorimeter is 8.87°C.
Explanation:
Volume of the water = V = 150 g
Density of the water , d =1.0 g/mL
Mass of the water = M
[tex]M=d\times V=1.00 g/mL\times 150 ml =150.0 g[/tex]
Mass of solution = m = M = 150.0 g
[tex]NaOH(s)\rightarrow NaOH(aq),\Delta H =-44.51 kJ/mol[/tex]
Moles of NaOH = [tex]\frac{5.00 g}{40 g/mol}=0.125 mol[/tex]
Energy released when 0.125 moles of NaOH added in water = Q
[tex]Q=0.125 moles\times (-44.51 kJ/mol)=-5.5638 kJ=-5,563.8 J[/tex]
1 kJ = 1000 J
Heat gained by water = Q' = -Q ( conservation of energy)
[tex]Q'= 5,563.8 J[/tex]
Specific heat of solution = c = 4.184 J/g°C
Change in temperature of the solution = [tex]\Delta T[/tex]
[tex]Q'=mc\times \Delta T[/tex]
[tex]5,563.8 J=150.0 g\times 4.184 J/g^oC\times \Delta T[/tex]
[tex]\Delta T=\frac{5,563.8 J}{150.0 g\times 4.184 J/g^oC}=8.87^oC[/tex]
The change in temperature of a coffee cup calorimeter is 8.87°C.
