contestada

A fan produces an air curtain to separate a loading dock from a cold storage room. The air curtain is a jet of air 10 ft wide, 0.5 ft thick moving with speed v = 30 ft/s the loss associated with this flow is (Kl)V^2/2 where Kl=5 how much power must the fan supply to the air to produce this flow?

Respuesta :

onyebuchinnaji

Answer:

The power the fan must supply to the air to produce this flow is 1.74 hp

Explanation:

Given;

Thickness of air curtain, h = 0.5 ft

Width of air curtain, w = 10 ft

speed of air flow, v = 30 ft/s

Area of flow, A = 0.5 x 10 = 5 ft²

volumetric flow rate, Q = A x v = 5 x 30 = 150 ft³/s

Energy loss associated with this flow = (Kl)V²/2

Given;

KI = 5

Energy loss associated with this flow = 5 x (30)²/2

                                                              = 2250 ft²/s²

Volumetric flow rate, Q = 2250 ft²/s² x 0.5 ft = 1125 ft³/s²

P = ΔpQ

At a constant pressure drop;

[tex]Power \ require \ to \ produce \ this \ flow =\frac{(1125+150)}{735} = 1.74\ hp[/tex]

Therefore, the power the fan must supply to the air to produce this flow is 1.74 hp

Otras preguntas