Answer:
85.2 feet
Step-by-step explanation:
Let the distance be 'd' and time be 't'.
Given:
Distance varies directly as the square of the time the object is in motion.
So,
[tex]d\propto t^2\\\\d=kt^2[/tex]
Where, 'k' is constant of proportionality.
Now, also given:
When d = 144.9 ft, t = 3 s
Plug in these value in the above equation to find 'k'. This gives,
[tex]144.9=3^2k\\\\k=\frac{144.9}{9}=16.1\ ft/s^2[/tex]
Now, we need to find 'd' when time 't' equals 2.3 s.
So, plug in the given values in the above equation to get the value of 'd'. This gives,
[tex]d=16.1\times (2.3)^2\\\\d=16.1\times 5.29=85.2\ ft[/tex]
Therefore, the distance traveled by the object to reach base is nothing but the height of cliff. So, height of cliff is 85.2 ft.
