At a certain temperature the rate of this reaction is first order in HI with a rate constant of :7.21s?1

2HI(g)??H2(g) + I2(g)

Suppose a vessel contains HI at a concentration of 0.440M

. Calculate the concentration of HI in the vessel 0.210 seconds later. You may assume no other reaction is important.

Round your answer to 2 significant digits.

Respuesta :

Answer:

The concentration of HI in the vessel after 0.210 seconds later will be 0.097 M.

Explanation:

Initial concentration of HI =[tex][A_o]=0.440 M[/tex]

Final concentration after t seconds = [A]

t = 0.210 seconds

Rate constant of reaction = k = [tex]7.21 s^{-1}[/tex]

The integrated rate law of first order kinetics :

[tex][A]=[A_o]\times e^{-kt}[/tex]

[tex][A]=0.440 M\times e^{-7.21 s^{-1}\times 0.210 s}[/tex]

[A] = 0.0968 M ≈ 0.097 M

The concentration of HI in the vessel after 0.210 seconds later will be 0.097 M.