Answer:
= 0.417 m/s
Explanation:
Momentum before throwing the rock: m*V = 95.0 kg * 0.460 m/s
= 44.27 N*s
A) man throws the rock forward
mass of rock m1 = 0.310 kg
V1 = 15.5 m/s, in the same direction of the sled with the man
sled and man:
m2 = 95 kg - 0.310 kg = 94.69 kg
v2 = ?
Conservation of momentum:
momentum before throw = momentum after throw
44.27N*s = 0.310kg * 15.5m/s + 94.69kg*v2
⇒ v2 = [44.27 N*s - 0.310 * 15.5N*s ] / 94.69 kg
= 0.417 m/s
Answer:
0.41 m/s.
Explanation:
Mt = 95 kg
Mr = 0.31 kg
Vr = 15.5m/s
Ut = 0.46 m/s
Mass of the man and sled = (95 - 0.31) kg
= 94.69 kg
Using conservation of momentum equation,
Momentum before the throw = momentum after the throw
95 × 0.46 = 0.31 × 15.5 + 94.69 × V2
43.7 = 4.805 + 94.69 V2
V2 = 0.41 m/s.
