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From the data on CAT scans in Exercise 8-45
(a) Find a two-sided 95% confidence interval for the standard
deviation.
(b) What should you do to address any reservations about the
confidence interval you found in part (a)?

A healthcare provider monitors the number of CAT
scans performed each month in each of its clinics. The most
recent year of data for a particular clinic follows (the reported
variable is the number of CAT scans each month expressed
as the number of CAT scans per thousand members of the
health plan):
2.31, 2.09, 2.36, 1.95, 1.98, 2.25, 2.16, 2.07, 1.88, 1.94, 1.97,
2.02.

Respuesta :

abidhussain7972

Answer:

Given n = 12

mean = summation(xi)/n = 2.08167

standard deviation = vsummation(xi - u)^2 / (n-1)

= 0.15637

a ) 95% CI = ( sqrt((n-1)s^2 / X^2a) , sqrt((n-1)s^2 / X^21-a) )

= ( sqrt(11*0.15637^2/21.92) , sqrt(11*0.15637^2/3.816) )

= ( 0.11077 , 0.26549 )

b ) We are 95% confident that the true standard deviations lie in the above given interval

Source : Chi square distribution table with df = 11 and alpha = 0.025 and 0.975

Explanation:

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