Respuesta :
Answer:
The value of change in internal energy of the gas = + 1850 J
Explanation:
Work done on the gas (W) = - 1850 J
Negative sign is due to work done on the system.
From the first law we know that Q = Δ U + W ------------- (1)
Where Q = Heat transfer to the gas
Δ U = Change in internal energy of the gas
W = work done on the gas
Since it is adiabatic compression of the gas so heat transfer to the gas is zero.
⇒ Q = 0
So from equation (1)
⇒ Δ U = - W ----------------- (2)
⇒ W = - 1850 J (Given)
⇒ Δ U = - (- 1850)
⇒ Δ U = + 1850 J
This is the value of change in internal energy of the gas.
The change in internal energy of gas will be "+1850 J".
Given:
Work done,
- W = -1850 J
By using the first law,
→ [tex]Q = \Delta U+W[/tex]
Since, it's a adiabatic compressor then
→ [tex]Q =0[/tex]
hence,
→ [tex]\Delta U = -W[/tex]
By substituting the values, we get
[tex]= -(-1850)[/tex]
[tex]= +1850 \ J[/tex]
Thus the above change is correct.
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