Respuesta :
Probability of the students having brown hair = 0.6
Probability of the students having brown eyes = 0.3
Probability of the students having both brown hair and brown eyes = 0.1
Step-by-step explanation:
Step 1 :
Given,
Percentage of the students having brown hair = 60%
Percentage of the students having brown eyes = 30%
Percentage of the students having both brown hair and brown eyes = 10%
We need to obtain the probability of each separately, when a student is chosen randomly
Step 2 :
The probability of each event happening given its percentage, can be obtained by dividing the corresponding percentage by 100.
Hence we have,
Probability of the students who have brown hair = [tex]\frac{60}{100}[/tex] = 0.6
Probability of the students who have brown eyes = [tex]\frac{30}{100}[/tex] = 0.3
Probability of the students who has both brown hair and eyes = [tex]\frac{10}{100}[/tex] = 0.1
Step 3 :
Answer :
Probability of the students who have brown hair = 0.6
Probability of the students who have brown eyes = 0.3
Probability of the students who has both brown hair and eyes = 0.1
Probability of student having brown hair, brown eyes & both = 0.6 ; 0.3 , 0.10 respectively
Probability is the likelihood of an event, calculated by dividing favourable outcomes by total outcomes.
Important Information
60% ie 60/100 students have brown hair, so probability of brown hair = 60/100 = 0.6
30% ie 30/100 students have brown eyes, so probability of brown eyes = 30/100 = 0.3
10% ie 10/100 students have both brown eyes & brown hair, so probability of brown eyes = 10/100 = 0.1
To learn more about Probability, refer https://brainly.com/question/743546?referrer=searchResults
