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For the reaction 2 HCl + Na2CO3 → 2 NaCl + H2O + CO2 8.0 moles of CO2 is collected at STP. What is the volume of CO2? 1) 57.6 L 2) 22.4 L 3) 0.0250 L 4) 2.80 L 5) 179 L 6) 0.357 L

Respuesta :

Answer : The correct option is, (5) 179 L

Explanation : Given,

Moles of [tex]CO_2[/tex] = 8.0 mole

The given chemical reaction is:

[tex]2HCl+Na_2CO_3\rightarrow 2NaCl+H_2O+CO_2[/tex]

As we know that, 1 mole of substance occupy 22.4 L volume of gas at STP.

As, 1 mole of [tex]CO_2[/tex] occupy 22.4 L volume of [tex]CO_2[/tex]

So, 8.0 mole of [tex]CO_2[/tex] occupy [tex]8.0\times 22.4=179.2L\approx 179L[/tex] volume of [tex]CO_2[/tex]

Thus, the volume of [tex]CO_2[/tex] is, 179 L

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