Answer:
a.9.028A
b. Opposite directions.
Explanation:
a. #Assume you have two long, parallel wires separated by a 2.5m distance. Given that [tex]F/L=3.9\times 10^-^5N/m[/tex], the two wires repel each other and the current in one wire is I=0.540A
#Magnitude of the force per unit length of wires is obtained as :
[tex]\frac{F}{L}=\frac{\mu I\prime I}{2\pi r}\\\\I \prime =(F/L)(2\pi r/\mu_oI)\\\\=(3.9\times 10^-^5N/m)(\frac{(2\pi 0.025m)}{(4\pi \times 10^-^7T.m)(0.54A)})\\\\=9.028A[/tex]
Hence the current in the second wire is 9.028A
b.We already know that the two wires parallel and as such attract each other.
-And for two parallel conductors carrying current in opposite directions repel each other.
-Since the two wires repel each other, then the curren in the second wire must flow in the opposite direction of the direction in the first.
# Hence the two wires are in opposite directions.
