Yes, Both are equivalent.
Step-by-step explanation:
Step 1:
To find the equality between the given terms Use the BODMAS (Brackets Orders Division Multiplication Addition Subtraction)
RHS SIDE:
[tex](1/8)-10*((3/4)-(3/8*X)+(5/8*X)[/tex]
Equation after 1st modification
[tex](1/8)-((15/2)-(15/4*X))+(5/8*X)[/tex]
Equation after Second modification
[tex]((1/8)-(15/2)+(15/4*X)+(5/8*X))[/tex]
Equation after Third modification
LCM 2,4,8 is 8
And taking LCM equation changes to [tex](1-60+30*X+5*X)/8[/tex]
Equation after Final modification
[tex](-59+35*X)/8[/tex] --------- 1
Step 2:
LHS SIDE:
[tex]-1/8*(59-35X)[/tex]
By applying the BODMAS rule in the above equation we will get
[tex](-59+35*X)/8[/tex] ------------ 2
From equations 1 & 2, the expression [tex](1/8)-(10*((3/4)-(3/8*X))+(5/8*X)[/tex] is equivalent to [tex](-1/8)*(59-35*X)[/tex]
