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You are holding a 1 kg rock and standing at the top of a cliff. You drop the rock off the cliff and it falls a distance 10 m. In this problem, you can ignore air resistance.
What is the change in the kinetic energy of the rock as it falls that distance?

Respuesta :

opudodennis

Answer:

98J

Explanation:

Given that the mass of the rock m=1kg, the height =10m and we know that gravitational force is [tex]g=9.8N/kg[/tex].

Change in kinetic energy  happens when the initial potential energy at rest is converted into Kinetic energy as:

[tex]\bigtriangleup KE=\bigtriangleup mgh\\\\=1kg\times 9.8\times10m\\\\=98J[/tex]

Hence, the change in kinetic energy of the rock is 98J

onyebuchinnaji

The change in the kinetic energy of the rock as it falls that distance is 98 J.

The given parameters;

mass of the rock, m = 1 kg

height of the cliff, h = 10 m

From the law of conservation of mechanical energy, the change in the kinetic energy is equal to change in the potential energy.

The change in the kinetic energy is calculated as;

[tex]\Delta K.E = \Delta P.E = mg(h_f - h_0)\\\\\Delta K.E = 1 \times 9.8(10 -0)\\\\\Delta K.E = 98 \ J[/tex]

Thus, the change in the kinetic energy of the rock as it falls that distance is 98 J.

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