Answer:
Step-by-step explanation:
The question is what is f(1) when f(x)= |x – 4| + 5?
Before we start, I want to mention that this function involves the absolute value. The absolute value is when a number is being described as the distance away from the number 0 on a line. When it comes to absolute values, the number is never a negative.
Fore example, |5| = 5, |-235| = 235
So let us go straight into the problem!
f(1)= |(1) – 4| + 5
f(1)= |(-3)| + 5
f(1)= 3 + 5
f(1)= 8
There you go! When we put in an x-value of 1 into the function we will get 8 as the output or outcome!
