Answer:
0.4kg/s
Explanation:
Where
[tex] Q_c_v = -10kw [/tex]
[tex] W_c_v = -90kw [/tex]
Using inlet and exit temperatures we have:
[tex] h_1 = 300.10KJ/g [/tex]
[tex] h_2 = 503.02KJ/g [/tex]
Therefore, solving for mass flow rate we use the formula:
[tex] m = Q_c_v - W_c_v / h_2 - h_1 [/tex]
[tex] m = [ (-10kw) - (-90kw) / (503.02 -300.19) KJ/Kg] [/tex]
[tex] = 0.394Kg/s [/tex]
Mass flow rate m= 0.394Kg/s
approximately 0.4Kg/s