Answer:
The velocity of the arrow after 3 seconds is 30.02 m/s.
Explanation:
It is given that,
An arrow is shot upward on the moon with velocity of 35 m/s, its height after t seconds is given by the equation:
[tex]h(t)=35t-0.83t^2[/tex]
We know that the rate of change of displacement is equal to the velocity of an object.
[tex]v(t)=\dfrac{dh(t)}{dt}\\\\v(t)=\dfrac{d(35t-0.83t^2)}{dt}\\\\v(t)=35-1.66t[/tex]
Velocity of the arrow after 3 seconds will be :
[tex]v(t)=35-1.66t\\\\v(t)=35-1.66(3)\\\\v(t)=30.02\ m/s[/tex]
So, the velocity of the arrow after 3 seconds is 30.02 m/s. Hence, this is the required solution.
