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Two radio antennas are separated by 1.60 mm . Both broadcast identical 750 MHz waves.
Part A) If you walk around the antennas in a circle of radius 10.0 mm , how many maxima will you detect?

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opudodennis

Answer:

20

Explanation:

Given the following information:

  • Distance between the antennas is d=1.60m
  • Frequency of the signals is f=750MHz
  • Radius of the circle is r=10m
  • Speed of light is c=3×108m/s

Expression for path difference is given as:

[tex]\bigtriangleup \phi=m\lambda[/tex]

And for wavelength as:

[tex]\lambda=\frac{c}{f}[/tex]

#substitute the values for wavelength:

[tex]\lambda=\frac{3\times 10^8}{750\times 10^6}=0.4m[/tex]

#Substituting the values for the ratio of distance to the wavelength;

[tex]\frac{d}{\lambda}=2/0.4\\d=5\lambda[/tex]

Hence,

[tex]\bigtriangleup \phi=d=5\lambda[/tex]

#there are total number of 4 meeting points for maximum constructive interference. Therefore, total number of maxima points are 5×4=20.

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