One of the hazards facing humans in space is space radiation: high energy charged particles emitted by the sun. During a solar flare the intensity of this radiation can reach lethal levels. One proposed method of protection for astronauts on the surface of the moon or Mars is an array of large electrically charged spheres placed high above areas where people live and work. The spheres would produce a strong electric field E to deflect the charge particles that make up space radiation. The spheres would be similar in construction to a Mylar balloon, with a thin electrically conducting layer on the outside surface on which a net + or-charge would be placed. A typical sphere might be 5m in diameter. (a) To repel electrons in the radiation from a solar flare each sphere must produce an Electric field 1 x 10° N/C at 25 m from the center of the sphere. What net charge on sphere is needed? (b) What is E just outside the surface of the sphere? (c) What is the direction of E just outside the sphere?) (d) What is the E value and direction inside a negatively charged sphere?

b) E just outside the sphere = k q / r² = ( 9.0 × 10 ⁹ N²m²/C² ) × - 0.07 C / 2.5² ( since the diameter is 5 m, the radius will be 5 m/2 = 2.5 m) = 100800000 approx 10⁸ N

c) the direction of E just outside the sphere will outward perpendicular the surface point to the charge sphere

d) Since the electric charge will be uniformly distributed on the surface of the sphere to favor a lower energy state which is more stable, the charge in the negatively charge sphere will be zero and consequently, the electric field inside the sphere will be zero.

tallinn tallinn · Answer 2 · 2022-02-04T16:02:43+01:00

When we Using the equation from calculating field of force are:

a) Then E = K q/ r²When where k = 9.0 × 10 ⁹ N²m²/C² and also net charge q is unknown, r, radius from the center of the sphere = 25 m
Then q = afterward that q = ( 1 × 10⁶ N/C) × 25² / ( 9.0 × 10 ⁹ N²m²/C² ) = - 0.0694 approx - 0.07 C since it must be repelled. then

b) when E just outside the sphere = k q / r² = ( 9.0 × 10 ⁹ N²m²/C² ) × - 0.07 C / 2.5² ( since the diameter is 5 m, the radius are going to be 5 m/2 = 2.5 m) = 100800000 approx 10⁸ N

c) When the direction of E just outside the sphere will are outward then perpendicular also the surface point to the charged sphere

d) Thus, Since the electrical charge are uniformly distributed on the surface of the sphere to favor a lower energy state which is more stable, also the charge within the charge sphere are visiting be zero and also after that consequently, then the electrical field inside the sphere are zero.

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