Answer:
59.4 N
Explanation:
The force exerted on a current-carrying wire due to a magnetic field perpendicular to the wire is given by
[tex]F=ILB[/tex]
where
I is the current in the wire
L is the length of the wire
B is the strength of the magnetic field
Here in this problem, we model the strike as a current-carrying wire, so we have:
I = 49,500 A is the current
L = 1 m is the length (we want to find the force per each meter of length)
[tex]B=12 G = 12\cdot 10^{-4} T[/tex] is the strength of the magnetic field
Therefore, the force on each meter of the current due to the magnetic field is:
[tex]F=(49,500)(1)(12\cdot 10^{-4})=59.4 N[/tex]
