Answer:
Since m<BCA=m<CAB=55°, it follows that |AB|=|AC|, this means triangle ABC is isosceles.
Step-by-step explanation:
In the diagram AB is parallel to DC.
This means that, by the alternate interior angles theorem?
[tex] \angle \: CAB = 55 \degree[/tex]
Also the sum of angles in a triangle should be 180° .
[tex]m \angle \: BCA = 55 \degree + 70 \degree = 180 \degree[/tex]
[tex]m \angle \: BCA = 180 - 55 - 70 = 55 \degree[/tex]
Since m<BCA=m<CAB=55°, it follows that |AB|=|AC|
Hence triangle ABC is isosceles.