Respuesta :
Answer: The pH of the solution is 1.41
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
Given mass of perchloric acid = 581.1 mg = 0.5811 g (Conversion factor: 1 g = 1000 mg)
Molar mass of perchloric acid = 100.5 g/mol
Volume of solution = 150 mL
Putting values in above equation, we get:
[tex]\text{Molarity of perchloric acid}=\frac{0.5811\times 1000}{100.5\times 150}\\\\\text{Molarity of perchloric acid}=0.0385M[/tex]
1 mole of perchloric acid produces 1 mole of [tex]H^+[/tex] ions and 1 mole of [tex]ClO_4^-[/tex] ions
To calculate the pH of the solution, we use the equation:
[tex]pH=-\log[H^+][/tex]
We are given:
[tex][H^+]=0.0385M[/tex]
Putting values in above equation, we get:
[tex]pH=-\log (0.0385)=1.41[/tex]
Hence, the pH of the solution is 1.41
The pH of the solution is 1.41 . The Molarity of the solution can be calculated and then pH can be determined.
Calculation of Molarity:
Molarity of solution= Number of moles of solute / Volume of solution in (L)
Given:
Mass of perchloric acid = 581.1 mg = 0.5811 g (Conversion factor: 1 g = 1000 mg)
Molar mass of perchloric acid = 100.5 g/mol
Volume of solution = 150 mL
Putting values in the above equation, we get:
Molarity of solution = 0.5811 * 1000 / 100.5 * 150
Molarity of solution= 0.0385 M
1 mole of perchloric acid produces 1 mole of H+ ions and 1 mole of ClO4- ions
Calculation of pH of the solution:
pH = -log[H+]
[H+]=0.0385 M
Putting values in above equation, we get:
pH= -log (0.0385)
pH = 1.41
Hence, the pH of the solution is 1.41.
Find more information about Molarity here:
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