Respuesta :
Answer:
a) L = 36.07 in
b) A = 9.1 in^2
Explanation:
The length of the pipe will be calculated using the formula of the deformation under tensile load. The required area can be obtained by dividing the load that is applied over the area of the cross section. We have the following data:
D = diameter = 5 mm
P = 127.5 ksi
E = 10.1 x 10^6 psi
δ = deformation = 0.05 in
σ = stress = 14 ksi
L =?
A =?
a)
δ = (P*L)/(A*E)
Clearing L:
L = (δ*A*E)/L = (δ*E)/σ = (0.05*10.1x10^6)/14x10^3 = 36.07 in
b)
A = P/σ = 127.5x10^3/14x10^3 = 9.1 in^2
a) The maximum allowable length of the pipe, L = 36.07 in
b) The required area of the pipe, A = 9.1 in²
Calculation for length and area:
The length of the pipe will be calculated using the formula of the deformation under tensile load. The required area can be obtained by dividing the load that is applied over the area of the cross section. We have the following data:
Given:
D = diameter = 5 mm
P = 127.5 ksi
E = [tex]10.1 * 10^6 psi[/tex]
δ = deformation = 0.05 in
σ = stress = 14 ksi
To find:
L =?
A =?
a) Calculation for length:
δ = (P*L)/(A*E)
L = (δ*A*E)/P
L= (δ*E)/σ
L= [tex](0.05*10.1*10^6)/14*10^3[/tex]
L= 36.07 in
b) Calculation for Area:
A = P/σ
A= [tex]127.5*10^3/14*10^3[/tex]
A= 9.1 in²
Find more information about Tensile load here:
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