Answer:
The force required to keep the plate in place is 251.36 N
Explanation:
Force = pressure × area
diameter (d) of the outlet of the nozzle = 8 cm = 8/100 = 0.08 m
area = πd^2/4 = 3.142×0.08^2/4 = 5.0272×10^-3 m^2
velocity of water (v) at the outlet = 10m/s
height (h) of water at the outlet = v^2/2g = 10^2/2×9.8 = 100/19.6 = 5.102 m
pressure = height × density of water × g = 5.102×1000×9.8 = 49999.6 N/m^2
Force = 49999.6 N/m^2 × 5.0272×10^-3 m^2 = 251.36 N
