For the given set of equations, none of the ordered pairs are solutions for it.
Step-by-step explanation:
Step 1:
From the given question,
[tex]6x-7y=4,[/tex] take this as equation 1,
[tex]-5x+3y=8[/tex], take this as equation 2.
Step 2:
We multiply equation 1 with 5 and equation 2 with 6, so we can cancel out the variable x in both equations. By doing this we get
[tex]30x-35y=20,[/tex], take this as equation 3.
[tex]-30x+18y=48[/tex],take this as equation 4.
When we add equations 3 and 4, the x variable is canceled out and y can be calculated.
[tex]-35y+18y=20+48, -17y=68, y = -4.[/tex]
Step 3:
Substituting this value of y in any of the previous equations we will get x's value.
Here this value of y is substituted in equation 1.
[tex]6x-7y=4, 6x - 7(-4)=4,[/tex]
[tex]6x = -24, x = -4.[/tex]
So we have [tex]x=-4[/tex] and [tex]y=-4[/tex].
None of the given ordered pairs have the solution as (-4, -4), so it is no for all the ordered pairs given.
