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A tennis player receives a shot with the ball (0.0631 kg) traveling horizontally at 53.7 m/s and returns the shot with the ball traveling horizontally 40.5 m/s in the opposite direction.
a. What is the impulse delivered to the ball by the racquet?
b. What work does the racquet do on the ball?

Respuesta :

Answer:

Explanation:

Impulse = change in momentum

= m ( v - u )

= .0631 ( 40.5 + 53.7 )

= 5.944 N.s

b )

Work done will be equal to change in kinetic energy

= 1/2 m ( 40.5² - 53.7² )

=  1/2 m ( 1640.25  - 2883.69)

= - 621.72 x m

= - 39.23 J

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