Answer:
The magnetic field is [tex]2\times 10^{-5}\ T[/tex].
Explanation:
Given that,
Current carried in the wire, I = 8 A toward the top of the page.
We need to find the magnetic field at point P, which is 8.00 cm to the right of the wire. The magnetic field is given by :
[tex]B=\dfrac{\mu_o I}{2\pi r}\\\\B=\dfrac{4\pi \times 10^{-7}\times 8}{2\pi \times 0.08}\\\\B=2\times 10^{-5}\ T[/tex]
So, the magnetic field is [tex]2\times 10^{-5}\ T[/tex]. Hence, this is the required solution.
