Answer:
z - score is 1.2
Step-by-step explanation:
We are given that the scores of adults on an IQ test is approximately normal with mean 100 and standard deviation 15 in which Corinne scores 118 .
So, z-score value is given by the formula, Z = [tex]\frac{X-\mu}{\sigma}[/tex] , where ; [tex]\mu[/tex] = Mean and [tex]\sigma[/tex] = standard deviation
Therefore, z - score of Corinne = [tex]\frac{118-100}{15}[/tex] = 1.2 .
