1. The grade point averages of a large population of college students is approximately normally distributed with mean 2.4 and standard deviation 0.8. A. What fraction of the students will possess a grade point average in excess of 3.0? B. What fraction of the students will have GPAs between 2.0 and 3.0?2. If students possessing a grade point average less than 1.9 are dropped from the college, what percentage of the students will be dropped?

Respuesta :

Answer:

(a) The percentage of GPA's more than 3.0 is 22.7%.

(b) The percentage of GPA's between 2.0 and 3.0 is 46.5%.

(c) The percentage of the students that will be dropped is 26.4%.

Step-by-step explanation:

Let X = the grade point averages of a large population of college students.

The random variable X is normally distributed with mean, μ = 2.4 and standard deviation, σ = 0.8.

(a)

Compute the probability of a student getting a GPA more than 3.0 as follows:

[tex]P(X>3.0)=P(\frac{X-\mu}{\sigma}>\frac{3.0-2.4}{0.8})\\=P(Z>0.75)\\=1-P(Z<0.75)\\=1-0.7734\\=0.2266[/tex]

The percentage of GPA's more than 3.0 is, 0.2266 × 100 = 22.7%

Thus, the percentage of GPA's more than 3.0 is 22.7%.

(b)

Compute the probability of a student getting a GPA between 2.0 and 3.0 as  follows:

[tex]P(2.0<X<3.0)=P(\frac{2.0-2.4}{0.8}<\frac{X-\mu}{\sigma}<\frac{3.0-2.4}{0.8})\\=P(-0.50<Z<0.75)\\=P(Z<0.75)-P(Z<-0.5)\\=0.7734-0.3085\\=0.4649[/tex]

The percentage of GPA's between 2.0 and 3.0 is, 0.4649 × 100 = 46.5%.

Thus, the percentage of GPA's between 2.0 and 3.0 is 46.5%.

(c)

Compute the probability of a students getting a GPA less than 1.9 as follows:

[tex]P(X<1.9)=P(\frac{X-\mu}{\sigma}<\frac{1.9-2.4}{0.8})\\=P(Z<-0.625)\=1-P(Z<0.625)\\=1-0.7357\\=0.2643[/tex]

The percentage of GPA's below 1.9 is, 0.2643 × 100 = 26.4%.

Thus, the percentage of the students that will be dropped is 26.4%.