Respuesta :
[tex]\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-8})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-8)}=\stackrel{m}{\cfrac{1}{4}}(x-\stackrel{x_1}{4}) \\\\\\ y+8=\cfrac{1}{4}x-1\implies y=\cfrac{1}{4}x-9[/tex]
Answer:
x-4y=28
Step-by-step explanation:
y-8=1/4(x-4)
y-8=1/4x-1
+8 +8
y=1/4x-7
4(y)=(1/4x-7)4
4y=x-28
-x -x
-1(-x+4y)=(-28)-1
x-4y=28
