A child sleds down a frictionless hill with vertical drop h. At the bottom is a level stretch where the coefficient of friction is 0.27.

If she slides 19 m across the level stretch, what's h? Express your answer with the appropriate units.

Velocity refers to the rate where the position changes. The average velocity should be considered as the displacement or position change.

Since

Velocity at the bottom of height h = √2gh

Here

μg , μ be the coefficient of friction

Now

= .27 x 9.8

= 2.646 m / s²

Now

v² = u² - 2as

0 = 2gh - 2 x 2.646 x 19

h = 2 x 2.646 x 19 / 2 x 9.8

= 5.13 m

Therefore, we can conclude that The height should be 5.13m.

Learn more about friction here: https://brainly.com/question/18519949

A child sleds down a frictionless hill with vertical drop h. At the bottom is a level stretch where the coefficient of friction is 0.27. If she slides 19 m across the level stretch, what's h? Express your answer with the appropriate units.

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A child sleds down a frictionless hill with vertical drop h. At the bottom is a level stretch where the coefficient of friction is 0.27.

If she slides 19 m across the level stretch, what's h? Express your answer with the appropriate units.