Answer:
[tex](a)a_{x}=248.9m/s^2\\(b)ratio=25.4[/tex]
Explanation:
Given data
Final Speed=224 m/s
initial speed=0 m/s
Distance=1070m
Time=0.900s
For Part (a) Acceleration
This is analysis model for particle under constant acceleration
In order to calculate the acceleration we will use following equations
[tex]a_{x}=\frac{v_{xf}-v_{xi}}{t}[/tex]
Substitute the given values
[tex]a_{x}=\frac{224m/s-0m/s}{0.900s}\\ a_{x}=248.9m/s^2[/tex]
For Part (B) the ratio of this acceleration to that of a freely falling body (g)
The ratio between both acceleration is given below as:
[tex]ratio=\frac{a_{x}}{a_{y}}\\ where\\a_{y}=g=9.8m/s^2\\So\\ratio=\frac{a_{x}}{g}\\ ratio=\frac{248.9m/s^2}{9.8m/s^2} \\ratio=25.4[/tex]
