Find the length of AB?
Round to the nearest tenth
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Answer:
AB ≈ 8.5
Step-by-step explanation:
[tex]a^{2} + b^{2} = c^{2} \\\\c = \sqrt{a^{2} + b^{2} } \\\\c = \sqrt{6^{2} + 6^{2} } \\\\c = \sqrt{36 + 36 } \\\\c = \sqrt{72 } \\\\c = 8.48528137424 \\[/tex]
c ≈ 8.5