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Consider a closed circuit with a 9-volt battery connected in series to a light bulb with a resistance of 3 ohms. What is the current flowing through the light bulb?

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Olajidey

Answer:

current flowing through the light bulb = 3A

Explanation:

current= voltage divided by Resistance

I = V/R

Given that,

resistance = 3 ohms

V = 9 volt

current = 9 volt /  3 ohms

= 3A

current flowing through the light bulb = 3A

Answer:

Current flowing through the light bulb = 3 Amps

Explanation:

Since the light bulb is a resistive load, it can obey ohm's law

Voltage across the battery, V = 9 volts

Resistance of the light bulb, R = 3 ohms

According to Ohm's law, V = IR

I = V/R

I = 9/3

I = 3 Amps

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